6x^2+72x-798=0

Solution for 6x^2+72x-798=0 equation:

6x^2+72x-798=0

a = 6; b = 72; c = -798;
Δ = b2-4ac
Δ = 722-4·6·(-798)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-156}{2*6}=\frac{-228}{12}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+156}{2*6}=\frac{84}{12}
=7
$